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JEE MAIN 2024
31.01.24 S2
Question
In the following circuit, the battery has an emf of 2 V and an internal resistance of $\frac{2}{3} \Omega$. The power consumption in the entire circuit is $W$.
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Solution
$\begin{aligned} & \text { Sol. } \quad \mathrm{R}_{\mathrm{eq}}=\frac{4}{3} \Omega \\ & \therefore \mathrm{P}=\frac{\mathrm{V}^2}{\mathrm{R}_{\mathrm{eq}}}=\frac{4}{4 / 3}=3 \mathrm{~W}\end{aligned}$
Question Tags
JEE Main
Physics
Medium
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