In the given figure $\mathrm{R}_1=10 \Omega, \mathrm{R}_2=8 \Omega, \mathrm{R}_3=4 \Omega$ and $\mathrm{R}_4=8 \Omega$. Battery is ideal with emf 12 V . Equivalent resistant of the circuit and current supplied by battery are respectively.
Select the correct option:
A
12Ω and 11.4 A
B
10.5Ω and 1.14A
C
10.5Ω and A
D
12Ω and 1A
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Here $R_2, R_3, R_4$ are in parallel
$$
\begin{aligned}
& \frac{1}{\mathrm{R}_{234}}=\frac{1}{\mathrm{R}_2}+\frac{1}{\mathrm{R}_3}+\frac{1}{\mathrm{R}_4} \\
& \mathrm{R}_{234}=2 \Omega
\end{aligned}
$$
$\mathrm{R}_{234}$ is in series with $\mathrm{R}_1$ so
$$
\begin{aligned}
& \mathrm{R}_{\mathrm{eq}}=\mathrm{R}_{234}+\mathrm{R}_1=2+10=12 \Omega \\
& \mathrm{i}=\frac{12}{12}=1 \mathrm{Amp}
\end{aligned}
$$
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