In the given reaction,
$$
\mathrm{X}+\mathrm{Y}+3 \mathrm{Z} \rightleftarrows \mathrm{XYZ}_3
$$
if one mole of each of $X$ and $Y$ with 0.05 mol of $Z$ gives compound $X Y Z_3$. (Given : Atomic masses of $X$, Y and Z are 10,20 and 30 amu, respectively). The yield of $\mathrm{XYZ}_3$ is $\_\_\_\_$ g. (Nearest integer)
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Solution
X + Y + 3Z ⇌ XYZ₃
1 mol 1 mol 0.05 mol
Z is L.R
0.05 / 3 = 1 mole of XYZ₃
Mass of XYZ₃ = 0.05 / 3 × (10 + 20 + 30 × 3) = 2 g
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