In the leaching of alumina from bauxite, the ore expected to leach out in the process by reacting with NaOH is:
Select the correct option:
A
$\mathrm{TiO}_2$
B
$\mathrm{Fe}_2 \mathrm{O}_3$
C
ZnO
D
$\mathrm{SiO}_2$
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Solution
In bauxite impurities of $\mathrm{Fe}_2 \mathrm{O}_3, \mathrm{TiO}_2$ and $\mathrm{SiO}_2$ are present, $\mathrm{Fe}_2 \mathrm{O}_3$ and $\mathrm{TiO}_2$ are basic oxides therefore does not reacts with or dissolve in NaOH whereas $\mathrm{SiO}_2$ is acidic oxide it gets dissolve in NaOH , hence leach out
$\mathrm{SiO}_2+2 \mathrm{NaOH} \rightarrow \mathrm{Na}_2 \mathrm{SiO}_3($ aq. $)+\mathrm{H}_2 \mathrm{O}$
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