Let $A=\left[\begin{array}{lll}2 & 0 & 1 \\ 1 & 1 & 0 \\ 1 & 0 & 1\end{array}\right], B=\left[B_1, B_2, B_3\right]$, where $B_1, \mathrm{~B}_2, \mathrm{~B}_3$ are column matrices, and
$$
\mathrm{AB}_1=\left[\begin{array}{l}
1 \\
0 \\
0
\end{array}\right], \mathrm{AB}_2=\left[\begin{array}{l}
2 \\
3 \\
0
\end{array}\right], \mathrm{AB}_3=\left[\begin{array}{l}
3 \\
2 \\
1
\end{array}\right]
$$
If $\alpha=|\mathrm{B}|$ and $\beta$ is the sum of all the diagonal elements of B , then $\alpha^3+\beta^3$ is equal to
