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JEE MAIN 2020
02-09-2020 S2
Question
A wire of density $9 \times 10^{-3} \mathrm{~kg} \mathrm{~cm}^{-3}$ is stretched between two clamps 1 m apart. The resulting strain in the wire is $4.9 \times 10^{-4}$. The lowest frequency of the transverse vibrations in the wire is (Young's modulus of wire $=x 10$ Y $910 \mathrm{Nm}^{-2}$ ), (to the nearest integer), $\_\_\_\_$ .
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Question Tags
JEE Main
Physics
Hard
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