\text { Let the arithmetic mean of } \frac{1}{a} \text { and } \frac{1}{b} \text { be } \frac{5}{16}, a>2 \text {. If } \alpha \text { is such that } a, 4, \alpha, b \text { are in A.P., then the equation } \alpha x^2-a x+2(\alpha-2 b)=0 \text { has: }