KBr is doped with $10^{-5}$ mole percent of $\mathrm{SrBr}_2$. The number of cationic vacancies in 1 g of KBr crystal is $\_\_\_\_$ 10¹4. (Round off to the Nearest Integer).
[Atomic Mass : K : $39.1 \mathrm{u}, \mathrm{Br}: 79.9 \mathrm{u}$,
$$
\left.N_A=6.023 \times 10^{23}\right]
$$
