Let $5 f(x)+4 fleft(frac{1}{x}right)=frac{1}{x}+3, x>0$.

JEE-Main 2023

08-04-2023_S1

Question

Let $5 f(x)+4 f\left(\frac{1}{x}\right)=\frac{1}{x}+3, x>0$. Then $18 \int_1^2 f(x) d x$ is equal to :

Select the correct option:

A

$10 \log _c 2-6$

B

$10 \log _e 2+6$

C

$5 \log _{\mathrm{e}} 2+3$

D

$5 \log _{\mathrm{e}} 2-3$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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