Let 9 distinct balls be distributed among 4 boxes, $B_1, B_2, B_3$ and $B_4$. If the probability than $B_3$ contains exactly 3 balls is then $\mathrm{k}\left(\frac{3}{4}\right)^9$ lies in the set:
Hello 👋 Welcome to Competishun – India’s most trusted platform for JEE & NEET preparation. Need help with JEE / NEET courses, fees, batches, test series or free study material? Chat with us now 👇