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JEE MAIN 2023
10-04-23 S1
Question
Let a common tangent to the curves $y^2=4 x$ and $(x-4)^2+y^2=16$ touch the curves at the points $P$ and $Q$. Then $(P Q)^2$ is equal to $\_\_\_\_$ .
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Question Tags
JEE Main
Mathematics
Easy
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