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JEE MAIN 2019
10-01-2019 S2
Question
Let $A=\left[\begin{array}{ccc}2 & b & 1 \\ b & b^2+1 & b \\ 1 & b & 2\end{array}\right]$ where $b>0$. Then find minimum value of $\frac{|A|}{b}$ is
Select the correct option:
A
$-\sqrt{3}$
B
$\sqrt{3}$
C
$2 \sqrt{3}$
D
$-2 \sqrt{3}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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