Let α and β be the roots of..... | JEE Main 2026

JEE MAIN 2026

21-01-2026 S2

Question

Let $\alpha$ and $\beta$ be the roots of the equation $x^2+2 a x+(3 a+10)=0$ such that $\alpha<1<\beta$. Then the set of all possible values of $a$ is :

Select the correct option:

$\left(-\infty, \frac{-11}{5}\right) \cup(5, \infty)$

$(-\infty,-2) \cup(5, \infty)$

$(-\infty,-3)$

$\left(-\infty, \frac{-11}{5}\right)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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