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JEE MAIN 2020
07-01-20 S1
Question
Let $\alpha$ and $\beta$ be two real roots of the equation $(\mathrm{k}+1) \tan ^2 \mathrm{x}-\sqrt{2} \cdot \lambda \tan \mathrm{x}=(1-\mathrm{k})$, where $\mathrm{k}(\neq-1)$ and $\lambda$ are real numbers. If $\tan ^2(\alpha+\beta)=50$, then a value of $\lambda$ is:
Select the correct option:
A
10
B
$10 \sqrt{2}$
C
5
D
$5 \sqrt{2}$
✓ Correct! Well done.
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Solution
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Question Tags
JEE Main
Mathematics
Medium
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