Let $\alpha, \beta$ be the roots of the equation $x^2-4 \lambda x+5=0$ and $\alpha, \gamma$ be the roots of the equation $\mathrm{x}^2-(3 \sqrt{2}+2 \sqrt{3}) \mathrm{x}+7+3 \lambda \sqrt{3}=0$
If $\beta+\gamma=3 \sqrt{2}$, then $(\alpha+2 \beta+\gamma)^2$ is equal to :
