Let $\alpha, \beta \in \mathbb{R}$ be such that the function $f(x)=\left\{\begin{array}{ll}2 \alpha\left(x^2-2\right)+2 \beta x & , x<1 \\ (\alpha+3) x+(\alpha-\beta) & , x \geq 1\end{array}\right.$ be differentiable at all $x \in \mathbb{R}$. Then $34(\alpha+\beta)$ is equal to