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JEE MAIN 2019
10-01-2019 S2
Question
Let $\alpha=(\lambda-2) \mathrm{a}+\mathrm{b}$ and $\beta=(4 \lambda-2) \mathrm{a}+3 \mathrm{~b}$ be two given vectors where vectors a and b are non-collinear. The value of $\lambda$ for which vectors $\vec{\alpha}$ are $\vec{\beta}$ collinear, is
Select the correct option:
A
–3
B
–4
C
3
D
4
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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