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JEE MAIN 2023
12-04-2023 S1
Question
Let C be the circle in the complex plane with centre $z_0=\frac{1}{2}(1+3 i)$ and radius $r=1$. Let $z_1=1+i$ and the complex number $z 2$ be outside the circle $C$ such that $|z 1-z 0||z 2-z 0|=1$. If $z 0, z 1$ and $z 2$ are collinear, then the smaller value of $|z 2|^2$ is equal to-
Select the correct option:
A
$\frac{13}{2}$
B
$\frac{5}{2}$
C
$\frac{3}{2}$
D
$\frac{7}{2}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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