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JEE-Main 2024
01.02.24_(S1)
Question
Let $C: x^2+y^2=4$ and $C^{\prime}: x^2+y^2-4 \lambda x+9=0$ be two circles. If the set of all values of $\lambda$ so that the circles C and $\mathrm{C}^{\prime}$ intersect at two distinct points, is $\mathbf{R}-[a, b]$, then the point $(8 a+12,16 b-20)$ lies on the curve:
Select the correct option:
A
$x^2+2 y^2-5 x+6 y=3$
B
$5 x^2-y=-11$
C
$x^2-4 y^2=7$
D
$6 x^2+y^2=42$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Question Tags
JEE Main
Mathematics
Hard
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