Report Issue

JEE MAIN 2023
10-4-2023 S2
Question
Let $f$ be a continuous function satisfying $\int_0^{t^2}\left(f(x)+x^2\right) d x=\frac{4}{3} t^3, \forall t>0$. Then $f\left(\frac{\pi^2}{4}\right)$ is equal to :
Select the correct option:
A
$\pi\left(1-\frac{\pi^3}{16}\right)$
B
$-\pi^2\left(1+\frac{\pi^3}{16}\right)$
C
$-\pi\left(1+\frac{\pi^3}{16}\right)$
D
$\pi^2\left(1-\frac{\pi^3}{16}\right)$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Easy
Start Preparing for JEE with Competishun