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JEE MAIN 2021
16-03-2021 S2
Question
Let $f: S \rightarrow$ Swhere $S=(0, \infty)$ be a twice differentiable function such that $\mathrm{f}(\mathrm{x}+1)= \mathrm{xf}(\mathrm{x})$. If $\mathrm{g}: \mathrm{S} \rightarrow \mathrm{R}$ be defined as $\mathrm{g}(\mathrm{x})=\log _{\mathrm{e}} \mathrm{f}(\mathrm{x})$, then the value of $\left|\mathrm{g}^{\prime \prime}(5)-\mathrm{g}^{\prime \prime}(1)\right|$ is equal to :
Select the correct option:
A
$\frac{205}{144}$
B
$\frac{197}{144}$
C
$\frac{187}{144}$
D
1
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Question Tags
JEE Main
Mathematics
Easy
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