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JEE MAIN 2025
02-04-2025 SHIFT-1
Question
Let $f:R \to R$ be a twice differentiable function such that $(\sin x\cos y)(f(2x + 2y) - f(2x - 2y)) = (\cos x\sin y)(f(2x + 2y) + f(2x - 2y))$ , for all $x,y \in R$. If ${f^\prime }(0) = \frac{1}{2}$, then the value of $24{f^{''}}\left( {\frac{{5\pi }}{3}} \right)$ is :
Select the correct option:
A
-2
B
2
C
3
D
-3
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Hard
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