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JEE Main 2021
26-08-2021 S1
Question
Let $f(x)=\cos \left(2 \tan ^{-1} \sin \left(\cos ^{-1} \sqrt{\frac{1-x}{x}}\right)\right) .0<x<1$. Then :
Select the correct option:
A
$(1-\mathrm{x})^2 \mathrm{f}^{\prime}(\mathrm{x})-2(\mathrm{f}(\mathrm{x}))^2=0$
B
$(1+x)^2 f(x)+2(f(x))^2=0$
C
$(1-x)^2 f^{\prime}(x)+2(f(x))^2=0$
D
$(1+x)^2 f(x)-2(f(x))^2=0$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Medium
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