Report Issue

JEE MAIN 2025
29-01-2025 SHIFT-1
Question
Let M and N respectively be the maximum and the minimum values of $f(x) = \left| {\begin{array}{*{20}{c}} {1 + {{\sin }^2}x}&{{{\cos }^2}x}&{4\sin 4x}\\ {{{\sin }^2}x}&{1 + {{\cos }^2}x}&{4\sin 4x}\\ {{{\sin }^2}x}&{{{\cos }^2}x}&{1 + 4\sin 4x} \end{array}} \right|,x \in {\rm{R}}$
Then ${M^4} - {m^4}$ is equal to :
Select the correct option:
A
1040
B
1295
C
1280
D
1215
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Easy
Start Preparing for JEE with Competishun