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JEE MAIN 2022
28-06-22 S2
Question
Let $\mathrm{a}>0, \mathrm{~b}>0$. Let e and $\ell$ respectively be the eccentricity and length of the latus rectum of the hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$. Let $e^{\prime}$ and $\ell$ respectively the eccentricity and length of the latus rectum of its conjugate hyperbola. If $\mathrm{e}^2=\frac{11}{14} \ell$ and $\left(\mathrm{e}^{\prime}\right)^2=\frac{11}{8} \ell^{\prime}$, then the value of $77 \mathrm{a}+44 \mathrm{~b}$ is equal to
Select the correct option:
A
100
B
110
C
120
D
130
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Hard
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