Let $\mathrm{n}_1<\mathrm{n}_2<\mathrm{n}_3<\mathrm{n}_4<\mathrm{n}_5$ be positivie integers such that $\mathrm{n}_1+\mathrm{n}_2+\mathrm{n}_3+\mathrm{n}_4+\mathrm{n}_5=20$. Then the number of such distinct arrangements $\left(\mathrm{n}_1, \mathrm{n}_2, \mathrm{n}_3, \mathrm{n}_4, \mathrm{n}_5\right)$ is
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