Report Issue

JEE MAIN 2025
02-04-2025 SHIFT-1
Question
Let one focus of the hyperbola $H:\frac{{{x^2}}}{{{a^2}}} - \frac{{{y^2}}}{{{b^2}}} = 1$ be at $(\sqrt {10} ,0)$ and the corresponding directrix be $x = \frac{9}{{\sqrt {10} }}$. If $e$ and $l$ respectively are the eccentricity and the length of the latus rectum of H, then $9\left( {{e^2} + l} \right)$ is equal to :
Select the correct option:
A
16
B
12
C
15
D
14
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Easy
Start Preparing for JEE with Competishun