Let P be a variable point on the parabola... | Parabola

JEE MAIN 2021

20-07-2021 S2

Question

Let $P$ be a variable point on the parabola $y=4 x^2+1$. Then, the locus of the mid-point of the point $P$ and the foot of the perpendicular drawn from the point $P$ to the line $y=x$ is :

Select the correct option:

$(3 x-y)^2+(x-3 y)+2=0$

$2(3 x-y)^2+(x-3 y)+2=0$

$(3 x-y)^2+2(x-3 y)+2=0$

$2(x-3 y)^2+(3 x-y)+2=0$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Medium

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