Let S be the set of values of $\lambda$, for which the system of equations
$$
\begin{aligned}
& 6 \lambda x-3 y+3 z=4 \lambda^2 \\
& 2 x+6 \lambda y+4 z=1
\end{aligned}
$$
$3 x+2 y+3 \lambda z=\lambda$ has no solution. Then $12 \sum_{i, e s}(\lambda]$ is equal to
