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JEE MAIN 2023
8-4-2023 S1
Question
Let $S_k=\frac{1+2+\ldots \ldots+K}{K}$ and $\sum_{j=1}^n S_j^2=\frac{n}{A}\left(B n^2+C n+D\right)$, where $A, B, C, D \in N$ and $A$ has least value. Then
Select the correct option:
A
A + B is divisible by D
B
A + B = 5 (D - C)
C
A + C + D is not divisible by B
D
A + B + C + D is divisible by 5
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Solution Image
Question Tags
JEE Main
Mathematics
Hard
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