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JEE MAIN 2022
24-06-2022 S2
Question
Let the maximum area of the triangle that can be inscribed in the ellipse $\frac{x^2}{a^2}+\frac{y^2}{4}=1, a>2$, having one of its vertices at one end of the major axis of the ellipse and one of its sides parallel to the y-axis, be$6 \sqrt{3}$ . Then the eccentricity of the ellipse is
Select the correct option:
A
$\frac{\sqrt{3}}{2}$
B
$\frac{1}{2}$
C
$\frac{1}{\sqrt{2}}$
D
$\frac{\sqrt{3}}{4}$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Question Tags
JEE Main
Mathematics
Medium
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