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JEE MAIN_2026_
220126_S1
Question
Let the solution curve of the differential equation $x d y-y d x=\sqrt{x^2+y^2} d x, x>0, y(1)=0$, be $y=y(x)$. Then $y(3)$ is equal to
Select the correct option:
A
4
B
6
C
1
D
2
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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