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JEE Main 2019
10-01-2019 S1
Question
Let $\vec{a}=2 \hat{i}+\lambda_1 \hat{j}+3 \hat{k}, \vec{b}=4 \hat{i}+\left(3-\lambda_2\right) \hat{j}+6 \hat{k}$ and $\vec{c}=3 \hat{i}+6 \hat{j}+\left(\lambda_3-1\right) \hat{k}$ be three vectors such that $\vec{b}=2 \vec{a}$ and $\vec{a}$ is perpendicular to $\vec{c}$. Then a possible value of $\left(\lambda_1, \lambda_2, \lambda_3\right)$ is :
Select the correct option:
A
(1, 3, 1)
B
(1, 5, 1)
C
$\left(\frac{1}{2}, 4,-2\right)$
D
$\left(-\frac{1}{2}, 4,0\right)$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Easy
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