Let $\vec{a}=6 \hat{i}+9 \hat{j}+12 \hat{k}, \vec{b}=\alpha \hat{i}+11 \hat{j}-2 \hat{k}$, and $\vec{c}$ be vectors such that $\vec{a} \times \vec{c}=\vec{a} \times \vec{b}, \vec{a} \cdot \vec{c}=-12, \vec{c}(\hat{i}-2 \hat{j}+\hat{k})=5$, then $\overrightarrow{\mathrm{c}}(\hat{\mathrm{i}}+\hat{\mathrm{j}}+\hat{\mathrm{k}})$ is equal to