Let $X=\left[\begin{array}{lll}0 & 1 & 0 \\ 0 & 0 & 1 \\ 0 & 0 & 0\end{array}\right], Y=\alpha l+\beta x+\gamma x^2$ and $Z=\alpha^2 \mid-\alpha \beta X+\left(\beta^2-\alpha \gamma\right) X^2, \alpha, \beta, \gamma \in \mathbb{R}$. If $Y-1=\left[\begin{array}{ccc}\frac{1}{5} & \frac{-2}{5} & \frac{1}{5} \\ 0 & \frac{1}{5} & \frac{-2}{5} \\ 0 & 0 & \frac{1}{5}\end{array}\right]$, then $(\alpha-\beta+\gamma)^2$ is equal to $\ldots$