Let y² = 12x be the parabola..... | JEE Main 2026

JEE MAIN 2026

21-01-2026 S2

Question

Let $y^2=12 x$ be the parabola with its vertex at O . Let P be a point on the parabola and A be a point on the $x$-axis such that $\angle \mathrm{OPA}=90^{\circ}$. Then the locus of the centroid of such triangles OPA is :

Select the correct option:

$y^2-6 x+4=0$

$y^2-9 x+6=0$

$y^2-2 x+8=0$

$y^2-4 x+8=0$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Mathematics

Easy

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