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JEE MAIN 2021
20-07-2021 S1
Question
Let $y=m x+c, m>0$ be the focal chord of $y^2=-64 x$, which is tangent to $(x+10)^2+y^2=4$. Then, the value of $4 \sqrt{2}(m+c)$ is equal to $\_\_\_\_$ .
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Question Tags
JEE Main
Mathematics
Medium
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