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JEE MAIN 2021
20-07-2021 S1
Question
Let $y=y(x)$ be the solution of the differential equation $e^x \sqrt{1-y^2} d x+\left(\frac{y}{x}\right) d y=0, y(1)=-1$. Then the value of $(y(3))^2$ is equal to :
Select the correct option:
A
$1-4 e^3$
B
$1-4 e^6$
C
$1+4 e^3$
D
$1+4 e^6$
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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