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JEE MAIN 2019
11-01-2019 S1
Question
Let $[\mathrm{x}]$ denote the greatest integer less than or equal to x . Then $\lim _{x \rightarrow 0} \frac{\tan \left(\pi \sin ^2 x\right)+(|x|-\sin (x[x]))^2}{x^2}$
Select the correct option:
A
equals 0
B
equals $\pi$ + 1
C
equals $\pi$
D
does not exist
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Mathematics
Medium
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