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JEE MAIN 2021
16-03-2021 S1
Question
$\mathrm{AB}_2$ is $10 \%$ dissociated in water to $\mathrm{A}^{2+}$ and $\mathrm{B}^{-}$. The boiling point of a 10.0 molal aqueous solution of AB 2 is $\_\_\_\_$ ${ }^{\circ} \mathrm{C}$ (Round off to the Nearest Integer). [Given : Molal elevation constant of water $\mathrm{K}_{\mathrm{b}}=0.5 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}$ boiling point of pure water $=100^{\circ} \mathrm{C}$ ]
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JEE Main
Chemistry
Easy
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