Contact us
Back

Report Issue

JEE MAINS 2024
31.01.24 S1
Question
The mass defect in a particular reaction is 0.4 g . The amount of energy liberated is $\mathrm{n} \times 10^7 \mathrm{kWh}$, where $\mathrm{n}=$ $\_\_\_\_$ . (speed of light $\left.=3 \times 10^8 \mathrm{~m} / \mathrm{s}\right)$
Write Your Answer
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
Sol. $$ \begin{aligned} & \mathrm{E}=\Delta \mathrm{mc}^2 \\ & =0.4 \times 10^{-3} \times\left(3 \times 10^8\right)^2 \\ & =3600 \times 10^7 \mathrm{kWs} \\ & =\frac{3600 \times 10^7}{3600} \mathrm{kWh}=1 \times 10^7 \mathrm{kWh} \end{aligned} $$
Question Tags
JEE Main
Physics
Medium
Start Preparing for JEE with Competishun
YouTube
App
Tests