CK_JEE-Main 12-4-19_S2 - Competishun – Live JEE & NEET Courses and Exam Prep

JEE MAIN 2019

12-04-2019 S2

Question

$\mathrm{NO}_2$ required for a reaction is produced by the decomposition of $\mathrm{N}_2 \mathrm{O}_5$ in $\mathrm{CCl}_4$ as per the equation, $2 \mathrm{~N}_2 \mathrm{O}_5(\mathrm{~g})$ $$ \rightarrow 4 \mathrm{NO}_2(\mathrm{~g})+\mathrm{O}_2(\mathrm{~g}) . $$ The initial concentration of $\mathrm{N}_2 \mathrm{O}_5$ is $3.00 \mathrm{~mol} \mathrm{~L}^{-1}$ and it is $2.75 \mathrm{~mol} \mathrm{~L}^{-1}$ after 30 minutes. The rate of formation of $\mathrm{NO}_2$ is

Select the correct option:

$1.667 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}$

$4.167 \times 10^{-3} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}$

$8.333 \times 10^{-3} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}$

$2.083 \times 10^{-3} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution