The mole fraction of a solvent| Mole Concept

JEE MAIN 2019

12-4-19_S1

Question

The mole fraction of a solvent in aqueous solution of a solute is 0.8 . The molality (in $\mathrm{mol} \mathrm{kg}-1$ ) of the aqueous solution is

Select the correct option:

$13.88 \times 10^{-2}$

$13.88 \times 10^{-3}$

13.88

$13.88 \times 10^{-1}$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Chemistry

Medium

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