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JEE MAIN 2025
23-01-2025 SHIFT-1
Question
$2.8\times {{10}^{{-3}}}~\text{mol}$ of $\text{C}{{\text{O}}_{2}}$ is left after removing ${{10}^{{21}}}$ molecules from its 'X' mg sample. The mass of $\text{C}{{\text{O}}_{2}}$ taken initially is
Given: ${{\text{N}}_{\text{A}}}=6.02\times {{10}^{{23}}}~\text{mo}{{\text{l}}^{{-1}}}$
Select the correct option:
A
48.2 mg
B
98.3 mg
C
196.2 mg
D
150.4 mg
✓ Correct! Well done.
✗ Incorrect. Try again or view the solution.
Solution
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Question Tags
JEE Main
Chemistry
Medium
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