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JEE MAIN 2024
31.01.24_(S1)
Question
Number of moles of methane required to produce $22 \mathrm{gCO}_{2(\mathrm{~g})}$ after combustion is $x \times 10^{-2}$ moles. The value of x is
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Solution
$$ \begin{aligned} & \mathrm{CH}_{4(\mathrm{~g})}+2 \mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CO}_{2(\mathrm{~g})}+2 \mathrm{H}_2 \mathrm{O}_{(\ell)} \\ & \mathrm{n}_{\mathrm{CO}_2}=\frac{22}{44}=0.5 \text { moles } \end{aligned} $$ So moles of $\mathrm{CH}_4$ required $=0.5$ moles i.e. $50 \times 10^{-2}$ mole $$ x=50 $$
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