Of the following four aqueous solutions, total number of those solutions whose freezing point is lower than that of $0.10 \mathrm{M} \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}$ is $\_\_\_\_$ (Integer answer)
(i) $0.10 \mathrm{M} \mathrm{Ba} 3\left(\mathrm{PO}_4\right)_2$
(ii) $0.10 \mathrm{M} \mathrm{Na}_2 \mathrm{SO}_4$
(iii) 0.10 M KCl
(iv) $0.10 \mathrm{M} \mathrm{Li}_3 \mathrm{PO}_4$
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Solution
“As 0.1 M NaCl is non-electrolyte and so it will give rise electrolyte so in each case effective molarity = 0.1 such will have lower freezing point.
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