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The reaction of compound P with $\mathrm{CH}_3 \mathrm{MgBr}$ (excess) in $\left(\mathrm{C}_2 \mathrm{H}_5\right)_2 \mathrm{O}$ followed by addition of $\mathrm{H}_2 \mathrm{O}$ gives Q. The compound Q on treatment with $\mathrm{H}_2 \mathrm{SO}_4$ at $0^{\circ} \mathrm{C}$ gives R . The reaction of R with $\mathrm{CH}_3 \mathrm{COCl}$ in the presence of anhydrous $\mathrm{AlCl}_3$ in $\mathrm{CH}_2 \mathrm{Cl}_2$ followed by treatment with $\mathrm{H}_2 \mathrm{O}$ produces compound S . [Et in compound $P$ is ethyl group]