Plotting 1/La against c/mm for weak acid... | Electrochemistry | JEE Advance

JEE Advance2023

Paper-1 2023

Question

Plotting $1 / \mathrm{L}_{\mathrm{a}}$ against $\mathrm{c} / \mathrm{mm}$ for aqueous solutions of a monobasic weak acid $(\mathrm{HX})$ resulted in a straight line with $y$-axis intercept of $P$ and slope of $S$. The ratio $P / S$ is- $\left[\omega_{a_2}=\right.$ molar conductivity

Select the correct option:

A

$\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\circ} \mid$

B

$\operatorname{Ka} \Lambda_m^{\circ} / 2$

C

$2 \mathrm{~K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\circ}$

D

$1 /\left(\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\circ}\right)$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Advance

Chemistry

Medium

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