Reaction of BeCl₂ with ammonia.... | JEE Main 2023

JEE MAIN 2023

24-01-2023 S1

Question

Reaction of BeQ with ammonia and hydrogen fluoride gives 'A' which on thermal decomposition gives $\mathrm{BeF}_2$ and $\mathrm{NH}_4 \mathrm{~F}$. What is ' A ' ?

Select the correct option:

$\left(\mathrm{NH}_4\right)_2 \mathrm{BeF}_4$

$\mathrm{H}_3 \mathrm{NBeF}_3$

$\left(\mathrm{NH}_4\right) \mathrm{BeF}_3$

$\left(\mathrm{NH}_4\right) \mathrm{Be}_2 \mathrm{H}_5$

✓ Correct! Well done.

✗ Incorrect. Try again or view the solution.

Solution

Question Tags

JEE Main

Chemistry

Easy

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