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JEE MAIN 2023
13-4-23 S2
Question
See the following chemical reaction:
$\mathrm{Cr}_2 \mathrm{O}_7^{2-}+\mathrm{XH}^{+}+6 \mathrm{Fe}^{2+} \rightarrow \mathrm{YCr}^{3+}+6 \mathrm{Fe}^{3+}+\mathrm{ZH}_2 \mathrm{O}$
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Solution
$\mathrm{Cr}_2 \mathrm{O}_7^{2-}+14 \mathrm{H}^{+}+6 \mathrm{Fe}^{2+} \rightarrow 6 \mathrm{Fe}^{3+}+2 \mathrm{Cr}^{3+}+7 \mathrm{H}_2 \mathrm{O}$ $$ \begin{aligned} & x=14 \\ & y=2 \\ & z=7 \end{aligned} $$ Hence $(x+y+z)=14+2+7=23$
Question Tags
JEE Main
Chemistry
Easy
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